Two Wires W1 And W2. two wires ${{w}_{1}}$ and ${{w}_{2}}$ have the same radius $r$ and respective densities ${{\rho }_{2}}=4{{\rho }_{1}}$. See the solution verified by toppr using hooke's law and the. We have two wires w1 and w2. two wires w 1 and w 2 are made of same material and have the same length. two wires w1 and w2 have the same radius r and respective densities ρ1 and ρ2 such that ρ2 =4 ρ1. Πr2f = y (4) for w 1. They are joined together at the point. two wires w1 and w2 have the same radius r and respective densities ρ 1 and ρ2 such that ρ2=4ρ1. on the other hand, if the thickness (diameter) of the wire is doubled, the current becomes 4 times. Two wires w 1 and w 2 of the same metal have the same. They are joined together at the point. Using, af = y l1δl1. They are joined together the point o, shown. two wires w_1 and w_2 have the same radius r and respective densities rho_2 = 4 rho_1.
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They are joined together at the point. See the solution verified by toppr using hooke's law and the. two wires w1 and w2 have the same radius r and respective densities ρ1 and ρ2 such that ρ2 =4 ρ1. two wires w_1 and w_2 have the same radius r and respective densities rho_2 = 4 rho_1. They are joined together at the point. two wires w 1 and w 2 are made of same material and have the same length. We have two wires w1 and w2. on the other hand, if the thickness (diameter) of the wire is doubled, the current becomes 4 times. Using, af = y l1δl1. two wires w1 and w2 have the same radius r and respective densities ρ 1 and ρ2 such that ρ2=4ρ1.
Solved Two long wires (W1,W2) lying perpendicular to the
Two Wires W1 And W2 two wires ${{w}_{1}}$ and ${{w}_{2}}$ have the same radius $r$ and respective densities ${{\rho }_{2}}=4{{\rho }_{1}}$. Πr2f = y (4) for w 1. two wires w1 and w2 have the same radius r and respective densities ρ1 and ρ2 such that ρ2 =4 ρ1. They are joined together at the point. Two wires w 1 and w 2 of the same metal have the same. See the solution verified by toppr using hooke's law and the. We have two wires w1 and w2. two wires w1 and w2 have the same radius r and respective densities ρ 1 and ρ2 such that ρ2=4ρ1. Using, af = y l1δl1. on the other hand, if the thickness (diameter) of the wire is doubled, the current becomes 4 times. two wires w_1 and w_2 have the same radius r and respective densities rho_2 = 4 rho_1. They are joined together at the point. two wires ${{w}_{1}}$ and ${{w}_{2}}$ have the same radius $r$ and respective densities ${{\rho }_{2}}=4{{\rho }_{1}}$. They are joined together the point o, shown. two wires w 1 and w 2 are made of same material and have the same length.
